robinquill + lamball = jelliette
Quick Answers
What do you get from breeding Robinquill and Lamball?
Robinquill + Lamball produces Jelliette in Palworld 1.0. The offspring species is determined by the breeding-power midpoint of both parents.
How do you breed Jelliette?
One of the easiest ways to breed Jelliette is pairing Robinquill with Lamball. Both parents are Common and Common tier respectively, making this combo accessible.
Why This Combo Works
Breeding Robinquill (breeding power 2260) with Lamball (breeding power 3050) targets a midpoint of 2655. The closest Pal to that value is Jelliette, making this a reliable way to obtain it.
Parent Details
Result: Jelliette
View Jelliette full guide →Frequently Asked Questions
Why does Robinquill + Lamball equal Jelliette?
Palworld breeding is deterministic: the child is the Pal whose breeding power is closest to the midpoint of both parents. Robinquill (2260) and Lamball (3050) average to 2655, and Jelliette is the nearest match.
Can the combo order be reversed?
Yes. Breeding Lamball + Robinquill gives the same result — parent order does not matter in Palworld.
Combo Insights
Efficiency
Rank #3 of 3 combos that produce jelliette by parent availability. Both parents are common Pals (Robinquill / Lamball) — the shortcut to jelliette early on. Catch them and breed immediately; no endgame Pals required.
Type Matchup
Jelliette is Water-type, and neither parent shares its full typing — so this combo is about access, not type synergy. For elemental coverage, pair the offspring with Grass-type Robinquill or Neutral-type Lamball in your party.
Passive Strategy
Jelliette has no fixed passives — everything comes from inheritance. Breed Artisan/Serious/Musclehead onto the parents first, then run this combo; a Special Cake significantly boosts multi-passive inheritance odds.
Alternative Combos for jelliette
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